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最短路 之 CODE[VS] 1077 多源最短路

时间:2015-12-07 20:48:23      阅读:172      评论:0      收藏:0      [点我收藏+]

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/*
  floyd算法
*/
 1 #include <iostream>
 2 #include <cstdlib>
 3 #include <cstdio>
 4 #include <cstddef>
 5 #include <iterator>
 6 #include <algorithm>
 7 #include <string>
 8 #include <locale>
 9 #include <cmath>
10 #include <vector>
11 #include <cstring>
12 #include <map>
13 #include <utility>
14 #include <queue>
15 #include <stack>
16 #include <set>
17 #include <functional>
18 using namespace std;
19 const int INF = 0x3f3f3f3f;
20 const int MaxN = 105;
21 const int modPrime = 3046721;
22 
23 int n;
24 int dp[MaxN][MaxN];
25 
26 
27 void Solve()
28 {
29     for (int k = 0; k < n; ++k)
30     {
31         for (int i = 0; i < n; ++i)
32         {
33             for (int j = 0; j < n; ++j)
34             {
35                 dp[i][j] = min(dp[i][j], dp[i][k] + dp[k][j]);
36             }
37         }
38     }
39     int Q;
40     scanf("%d", &Q);
41     int src, dsn;
42     for (int i = 0; i < Q; ++i)
43     {
44         scanf("%d %d", &src, &dsn);
45         printf("%d\n", dp[src - 1][dsn - 1]);
46     }
47 }
48 
49 int main()
50 {
51 #ifdef HOME
52     freopen("in", "r", stdin);
53     //freopen("out", "w", stdout);
54 #endif
55 
56     scanf("%d", &n);
57     for (int i = 0; i < n; ++i)
58     {
59         for (int j = 0; j < n; ++j)
60         {
61             scanf("%d", &dp[i][j]);
62         }
63     }
64     Solve();
65 
66 #ifdef HOME
67     cerr << "Time elapsed: " << clock() / CLOCKS_PER_SEC << " ms" << endl;
68     _CrtDumpMemoryLeaks();
69 #endif
70     return 0;
71 }

 

 

最短路 之 CODE[VS] 1077 多源最短路

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原文地址:http://www.cnblogs.com/shijianming/p/5026792.html

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