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https://leetcode.com/problems/isomorphic-strings/
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given “egg”, “add”, return true.
Given “foo”, “bar”, return false.
Given “paper”, “title”, return true.
Note:
You may assume both s and t have the same length.
class Solution { private: typedef unordered_map<char, char> UMP; public: bool isIsomorphic(string s, string t) { if (s == t) return true; UMP A, B; int n = s.length(); for (int i = 0; i < n; i++) { char x1 = s[i], x2 = t[i]; if (A.find(x1) == A.end()) A[x1] = x2; else if (A[x1] != x2) return false; if (B.find(x2) == B.end()) B[x2] = x1; else if (B[x2] != x1) return false; } return true; } };
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原文地址:http://www.cnblogs.com/GadyPu/p/5028171.html