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You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
public class Solution { public static ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode l3 = new ListNode(-1); ListNode l3head=l3; if(l1==null) return l2; if(l2==null) return l1; int carry=0; while(l1!=null||l2!=null){ if(l1!=null){ carry +=l1.val; l1=l1.next; } if(l2!=null){ carry += l2.val; l2=l2.next; } l3.next=new ListNode(carry%10); carry=carry/10; l3=l3.next; } if(carry==1){ l3.next=new ListNode(1); } return l3head.next; } public static void main(String[] args) { ListNode l1=new ListNode(2); l1.next=new ListNode(4); l1.next.next=new ListNode(3); ListNode l2=new ListNode(5); l2.next=new ListNode(6); l2.next.next=new ListNode(4); ListNode anwer=addTwoNumbers(l1,l2); System.out.println(anwer.val+" "+anwer.next.val+" "+anwer.next.next.val); } }
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原文地址:http://www.cnblogs.com/WillsCheng/p/5031563.html