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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
运用递归
class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
if (p ==NULL&& q ==NULL)
return true;
if (p ==NULL|| q ==NULL)
return false;
else
{
if(p->val != q->val )
return false;
else
return isSameTree(p->left,q->left) && isSameTree(p->right,q->right);
}
}
};
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原文地址:http://www.cnblogs.com/gofighting/p/5033192.html