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题目链接：http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=481
| 13916935 | 540 | Team Queue | Accepted | C++ | 0.339 | 2014-07-21 06:07:37 |
Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for example.
In a team queue each element belongs to a team. If an element enters the queue, it first searches the
queue from head to tail to check if some of its teammates (elements of the same team) are already
in the queue. If yes, it enters the queue right behind them. If not, it enters the queue at the tail and
becomes the new last element (bad luck). Dequeuing is done like in normal queues: elements are
processed from head to tail in the order they appear in the team queue.
Your task is to write a program that simulates such a team queue.
The input file will contain one or more test cases. Each test case begins with the number of teams t
(
). Then t team descriptions follow, each one consisting of the number of elements
belonging to the team and the elements themselves. Elements are integers in the range 0 - 999999.
A team may consist of up to 1000 elements.
Finally, a list of commands follows. There are three different kinds of commands:
The input will be terminated by a value of 0 for t.
Warning: A test case may contain up to 200000 (two hundred thousand) commands, so the
implementation of the team queue should be efficient: both enqueing and dequeuing of an element
should only take constant time.
For each test case, first print a line saying ``Scenario #k", where k is the number of the test case. Then, for each DEQUEUE command, print the element which is dequeued on a single line. Print a blank line after each test case, even after the last one.
2 3 101 102 103 3 201 202 203 ENQUEUE 101 ENQUEUE 201 ENQUEUE 102 ENQUEUE 202 ENQUEUE 103 ENQUEUE 203 DEQUEUE DEQUEUE DEQUEUE DEQUEUE DEQUEUE DEQUEUE STOP 2 5 259001 259002 259003 259004 259005 6 260001 260002 260003 260004 260005 260006 ENQUEUE 259001 ENQUEUE 260001 ENQUEUE 259002 ENQUEUE 259003 ENQUEUE 259004 ENQUEUE 259005 DEQUEUE DEQUEUE ENQUEUE 260002 ENQUEUE 260003 DEQUEUE DEQUEUE DEQUEUE DEQUEUE STOP 0
Scenario #1 101 102 103 201 202 203 Scenario #2 259001 259002 259003 259004 259005 260001
解题思路：利用map的特性来存储每个人的队伍编号，利用queue的特性来模拟题意锁描述的操作方式。code是从粉书上读懂之后，半写半对拍下来的，以后仍需努力。
1 #include <iostream> 2 #include <cstring> 3 #include <cctype> 4 #include <cstdio> 5 #include <cstdlib> 6 #include <algorithm> 7 #include <map> 8 #include <queue> 9 #include <numeric> 10 using namespace std; 11 12 const int maxt = 1e3 + 10; 13 14 int main () { 15 int t, kase = 0; 16 int cnt = 0; 17 while (cin >> t && t) { 18 //cout << "***" << endl; 19 printf("Scenario #%d\n", ++cnt); 20 //记录所有人的团队编号 21 map<int, int> team; 22 for (int i = 0; i < t; ++ i) { 23 int n, x; 24 cin >> n; 25 while (n --) { 26 cin >> x; team[x] = i; 27 } 28 } 29 30 queue<int> q, q2[maxt]; 31 for (; ;) { 32 int x; 33 string cmd; 34 cin >> cmd; 35 if (cmd[0] == ‘S‘) { 36 break; 37 } else if (cmd[0] == ‘D‘) { 38 int t = q.front(); 39 cout << q2[t].front() << endl; 40 q2[t].pop(); 41 if (q2[t].empty()) q.pop(); //团体t全体出队列 42 } else if (cmd[0] == ‘E‘) { 43 cin >> x; 44 int t = team[x]; 45 if (q2[t].empty()) q.push(t); //团体t进入队列 46 q2[t].push(x); 47 } 48 } 49 cout << endl; 50 } 51 return 0; 52 }
UVa540.Team Queue,布布扣,bubuko.com
标签：des style blog http color os
原文地址：http://www.cnblogs.com/Destiny-Gem/p/3858338.html
