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leetcode Count and Say

时间:2015-12-11 22:04:25      阅读:156      评论:0      收藏:0      [点我收藏+]

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题目连接

https://leetcode.com/problems/count-and-say/ 

Count and Say

Description

The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.
Given an integer n, generate the $n^{th}$ sequence.

Note: The sequence of integers will be represented as a string.

直接模拟。。

class Solution {
public:
	string countAndSay(int n) {
		char ch;
		int m, tot = 0;
		string ans = "1";
		while (--n) {
			string ret = "";
			m = ans.length();
			for (int j = 0; j < m;) {
				tot = 0;
				ch = ans[j];
				for (; ch == ans[j]; j++) tot++;
				ret += to_string(tot) + ch;
			}
			ans = ret;
		}
		return ans;
	}
};

leetcode Count and Say

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原文地址:http://www.cnblogs.com/GadyPu/p/5040153.html

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