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236.Lowest Common Ancestor of a Binary Tree

时间:2015-12-12 16:55:35      阅读:186      评论:0      收藏:0      [点我收藏+]

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Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.

According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”

        _______3______
       /                  ___5__          ___1__
   /      \        /         6      _2       0       8
         /           7   4

For example, the lowest common ancestor (LCA) of nodes 5 and 1 is 3. Another example is LCA of nodes 5 and 4 is 5, since a node can be a descendant of itself according to the LCA definition.

方法:递归。如果root为空或者root为p或者q节点,那么直接返回root。递归求左右子树中是否有p和q的最近公共祖先。如果左右子树递归求得的结果均不为空,那么表示p和q分属左右子树,直接返回root,否则p和q均属于左子树或者右子树,那么返回递归求出来的结果。
  1. /**
  2. * Definition for a binary tree node.
  3. * struct TreeNode {
  4. * int val;
  5. * TreeNode *left;
  6. * TreeNode *right;
  7. * TreeNode(int x) : val(x), left(NULL), right(NULL) {}
  8. * };
  9. */
  10. class Solution {
  11. public:
  12. TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
  13. if(!root||p==root||q==root)
  14. return root;
  15. TreeNode * left =lowestCommonAncestor(root->left,p,q);
  16. TreeNode * right=lowestCommonAncestor(root->right,p,q);
  17. if(left&&right)//p和q分属root两边
  18. return root;
  19. return left? left:right;//p和q只是位于左右子树之中的一个
  20. }
  21. };





236.Lowest Common Ancestor of a Binary Tree

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原文地址:http://www.cnblogs.com/zhoudayang/p/5041425.html

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