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Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself. For example, Given "egg", "add", return true. Given "foo", "bar", return false. Given "paper", "title", return true. Note: You may assume both s and t have the same length.
Use HashMap, but HashMap does not guarantee values() set to be unique. Here we require no two characters may map to the same character. So we should also check if map.values() have duplicates. If yes, return false.
1 public class Solution { 2 public boolean isIsomorphic(String s, String t) { 3 if (s==null || t==null || s.length() != t.length()) return false; 4 HashMap<Character, Character> map = new HashMap<Character, Character>(); 5 for (int i=0; i<s.length(); i++) { 6 if (!map.containsKey(s.charAt(i))) { 7 if (!(map.values().contains(t.charAt(i)))) { 8 map.put(s.charAt(i), t.charAt(i)); 9 } 10 else return false; 11 } 12 else if (map.get(s.charAt(i)) != t.charAt(i)) return false; 13 } 14 return true; 15 } 16 }
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原文地址:http://www.cnblogs.com/EdwardLiu/p/5047711.html