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Given a binary tree
struct TreeLinkNode { TreeLinkNode *left; TreeLinkNode *right; TreeLinkNode *next; }
Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL
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Initially, all next pointers are set to NULL
.
Note:
For example,
Given the following perfect binary tree,
1 / 2 3 / \ / 4 5 6 7
After calling your function, the tree should look like:
1 -> NULL / 2 -> 3 -> NULL / \ / 4->5->6->7 -> NULL
/** * Definition for binary tree with next pointer. * struct TreeLinkNode { * int val; * TreeLinkNode *left, *right, *next; * TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {} * }; */ class Solution { public: void dfs(TreeLinkNode* root1,TreeLinkNode* root2){ if(!root1) return; root1->next = root2; dfs(root1->left,root1->right); if(!root2) return; dfs(root1->right,root2->left); dfs(root2->left,root2->right); } void connect(TreeLinkNode *root) { if(!root) return ; dfs(root->left,root->right); } };
Populating Next Right Pointers in Each Node
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原文地址:http://www.cnblogs.com/zengzy/p/5054982.html