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Given an integer n, return the number of trailing zeroes in n!.
Note: Your solution should be in logarithmic time complexity.
class Solution { public: int trailingZeroes(int n) { int res = 0; while(n){ res += n/5; n /= 5; } return res; } };
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原文地址：http://www.cnblogs.com/zengzy/p/5057928.html
