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Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom. For example, Consider the following matrix: [ [1, 4, 7, 11, 15], [2, 5, 8, 12, 19], [3, 6, 9, 16, 22], [10, 13, 14, 17, 24], [18, 21, 23, 26, 30] ] Given target = 5, return true. Given target = 20, return false.
The same with Lintcode: Search a 2D Matrix II
1 public class Solution { 2 public boolean searchMatrix(int[][] matrix, int target) { 3 int m = matrix.length; 4 int n = matrix[0].length; 5 if (matrix==null || m==0 || n==0) return false; 6 int i=0, j=n-1; 7 while (i<m && j>=0) { 8 if (matrix[i][j] == target) return true; 9 else if (matrix[i][j] > target) { 10 j--; 11 } 12 else i++; 13 } 14 return false; 15 } 16 }
Leetcode: Search a 2D Matrix II
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原文地址:http://www.cnblogs.com/EdwardLiu/p/5060662.html