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| package cn.edu.xidian.sselab.array; /** * * @author zhiyong wang * title:Remove Duplicates from Sorted Array * content: * Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. * Do not allocate extra space for another array, you must do this in place with constant memory. * For example, * Given input array nums = [1,1,2], * Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn‘t matter what you leave beyond the new length. */ public class RemoveDuplicatesfromSortedArray { //这个题与RemoveElement几乎相同，因为是已经排好序的数组，比较条件改成相邻的两个数进行比较 //同样是统计double的数字的对数，每个数前移相同的数字的个数 //不过比较的时候要注意问题，不要越界，这里特别主要，nums里面个数小于2个时候，不做任何处理，只有多于1个时才会进行比较 public int removeDuplicates(int[] nums){ int length = nums.length; int count = 0; if(length>1){ for(int i=1;i<length;i++){ if(nums[i-1] == nums[i]){ count++; }else{ nums[i-count] = nums[i]; } } } return length-count; } } |
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Remove Duplicates from Sorted Array
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原文地址：http://www.cnblogs.com/wzyxidian/p/5062185.html
