标签:
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 19177 Accepted Submission(s): 7033
题解:水题;
代码:
#include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #include<cmath> #include<queue> #include<stack> #include<vector> #include<map> #include<string> using namespace std; const int INF=0x3f3f3f3f; const double PI=acos(-1.0); #define mem(x,y) memset(x,y,sizeof(x)) #define SI(x) scanf("%d",&x) #define SL(x) scanf("%lld",&x) #define PI(x) printf("%d",x) #define PL(x) printf("%lld",x) #define P_ printf(" ") #define T_T while(T--) typedef long long LL; int score[15]; int ans; int G; struct Node{ char s[25]; int len; int m[15]; int tot; Node init(){ tot=0; int len; scanf("%s",s); scanf("%d",&len); for(int i=0;i<len;i++) scanf("%d",&m[i]),tot+=score[m[i]]; if(tot>=G)ans++; } friend int operator < (Node a,Node b){ if(a.tot!=b.tot)return a.tot>b.tot; else return strcmp(a.s,b.s)<0; } }; Node m[1010]; int main(){ int N,M,len; while(SI(N),N){ SI(M);SI(G); for(int i=1;i<=M;i++)SI(score[i]); ans=0; for(int i=0;i<N;i++){ m[i].init(); } sort(m,m+N); printf("%d\n",ans); for(int i=0;i<N;i++){ if(m[i].tot>=G) printf("%s %d\n",m[i].s,m[i].tot); else break; } } return 0; }
标签:
原文地址:http://www.cnblogs.com/handsomecui/p/5087042.html