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题目:
Given a set of distinct integers, nums, return all possible subsets.
Note:
For example,
If nums = [1,2,3]
, a solution is:
[ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ]
思路:
借用上一道题Combinations的代码
package recursion; import java.util.ArrayList; import java.util.Arrays; import java.util.List; public class Subsets { public List<List<Integer>> subsets(int[] nums) { List<List<Integer>> res = new ArrayList<List<Integer>>(); List<Integer> record = new ArrayList<Integer>(); Arrays.sort(nums); int n = nums.length; for (int k = 0; k <= n; ++k) generateRecord(res, record, nums, 0, n - 1, k); return res; } private void generateRecord(List<List<Integer>> res, List<Integer> record, int[] nums, int start, int end, int k) { if (k == 0) { res.add(record); return; } for (int i = start; i <= end - k + 1; ++i) { List<Integer> newRecord = new ArrayList<Integer>(record); newRecord.add(nums[i]); generateRecord(res, newRecord, nums, i + 1, end, k - 1); } } public static void main(String[] args) { // TODO Auto-generated method stub Subsets s = new Subsets(); int[] nums = { 1, 2, 3 }; List<List<Integer>> res = s.subsets(nums); for (List<Integer> l : res) { for (int i : l) System.out.print(i + "\t"); System.out.println(); } } }
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原文地址:http://www.cnblogs.com/shuaiwhu/p/5094671.html