标签:
题目:http://www.lydsy.com/JudgeOnline/problem.php?id=3527
设f[i]=q[i],g[i]=1/(i^2)
E[i]=∑f[j]*g[i-j](1≤j≤i)-∑f[j]*g[i-j](i+1≤j≤n)
左边做卷积,右边就令t=n-i,f‘[i]=f[n-i],右边就变成∑f‘[j]-g[t-j](0≤j≤t)
设a[i]=f[i]*g[i],b[i]=f‘[i]*g[i]
那么ans[i]=a[i]*b[n-i]
#include<cstring> #include<iostream> #include<cstdio> #include<algorithm> #include<map> #include<complex> #define rep(i,l,r) for (int i=l;i<=r;i++) #define down(i,l,r) for (int i=l;i>=r;i--) #define clr(x,y) memset(x,y,sizeof(x)) #define maxn 350050 #define mm 1000000007 #define pi acos(-1) #define ll long long using namespace std; typedef complex<double> E; E a[maxn],b[maxn],f[maxn],_f[maxn],g[maxn]; double x; int n,m,L,rev[maxn]; ll read(){ ll x=0,f=1; char ch=getchar(); while (!isdigit(ch)){if (ch==‘-‘) f=-1; ch=getchar();} while (isdigit(ch)){x=x*10+ch-‘0‘; ch=getchar();} return x*f; } void fft(E *a,int f){ rep(i,0,n-1) if (i>rev[i]) swap(a[i],a[rev[i]]); for (int i=1;i<n;i<<=1){ E wn(cos(pi/i),f*sin(pi/i)); for (int j=0,p=i<<1;j<n;j+=p){ E w(1,0); for (int k=0;k<i;k++,w=w*wn){ E x=a[j+k],y=w*a[j+k+i]; a[j+k]=x+y,a[j+k+i]=x-y; } } } if (f==-1) rep(i,0,n-1) a[i]/=n; } int main(){ n=read(); rep(i,1,n) { scanf("%lf",&x); f[i]=x; _f[n-i]=x; } rep(i,1,n) g[i]=1.0/i/i; m=n*2; for (n=1;n<=m;n<<=1) L++; rep(i,0,n) rev[i]=rev[i>>1]>>1|((i&1)<<(L-1)); fft(f,1); fft(_f,1); fft(g,1); rep(i,0,n-1) a[i]=f[i]*g[i]; rep(i,0,n-1) b[i]=_f[i]*g[i]; fft(a,-1); fft(b,-1); rep(i,1,m/2) printf("%.3lf\n",a[i].real()-b[m/2-i].real()); return 0; }
标签:
原文地址:http://www.cnblogs.com/ctlchild/p/5100405.html