身份证号码合法性判断

标签：blog   http   io   2014   for   问题   

8、输入：”511002198808081234”，函数返回值：0；

C代码如下：

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

int verifyIDCard(char* input);
int is_leapyear(int year);
int getyear(char* input);
int getmonth(char* input);
int getday(char* input);
int check_1to17(char* input);
int check18(char* input);
int chech_year_month_day(int year, int month, int day);

int main()
{
	char input[8][100] = {"511002111222","511002abc123456789",
	"51100219880808123a","511002188808081234","511002198813081234",
	"511002198808321234","511002198902291234","511002198808081234"};
	int i;
	for(i=0; i<8; i++)
	{
		printf("the IDcard is: %s, the result is: %d\n",input[i],verifyIDCard(input[i]));
	}
	return 0;
}

int is_leapyear(int year)
{
	if(( (year%4==0) && (year%400!=0) ) || (year%400==0))
		return 1;
	return 0;
}

int getyear(char* input)
{
	int year=0;
	year = (input[6]-'0') * 1000 + (input[7]-'0') * 100 +
		(input[8]-'0') * 10 + (input[9]-'0');
	return year;
}

int getmonth(char* input)
{
	int month=0;
	month = (input[10]-'0') * 10 + (input[11]-'0');
	return month;
}

int getday(char* input)
{
	int day=0;
	day = (input[12]-'0') * 10 + (input[13]-'0');
	return day;
}

int check_1to17(char* input)
{
	int i;
	for(i=0; i<17; i++)
		if( !(input[i]>='0' && input[i]<='9') )
			return 0;
	return 1;
}

int check18(char* input)
{
	char ch = input[17];
	if( (ch=='x') || (ch>='0' && ch<='9') )
		return 1;
	else
		return 0;
}

int check_year_month_day(int year, int month, int day)
{
	int leap;
	leap = is_leapyear(year);
	if(year<1900 || year>2100)
		return 4;
	if(month<1 || month>12)
		return 5;
	switch(month)
	{
	case 1:
	case 3:
	case 5:
	case 7:
	case 8:
	case 10:
	case 12:
		{
			if(day<1 || day>31)
				return 6;
			break;
		}
	case 4:
	case 6:
	case 9:
	case 11:
		{
			if(day<1 || day>30)
				return 6;
			break;
		}
	case 2:
		{
			if(leap)
			{
				if(day<1 || day>29)
					return 6;
				break;
			}
			else
			{
				if(day<1 || day>28)
					return 6;
				break;
			}
		}
	}
	return 0;
}

int verifyIDCard(char* input)
{
	int year,month,day;
	if(strlen(input)!=18)
		return 1;
	else
	{
		if(!check_1to17(input))
			return 2;
		else
		{
			 if(!check18(input))
				 return 3;
			 else
			 {
				year = getyear(input);
				month = getmonth(input);
				day = getday(input);
				return check_year_month_day(year,month,day);
			 }
		}
	}
}

身份证号码合法性判断,布布扣,bubuko.com

身份证号码合法性判断

标签：blog   http   io   2014   for   问题   

原文地址：http://blog.csdn.net/hs794502825/article/details/38051305