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Leet code —Jump Game

时间:2014-07-23 00:04:37      阅读:216      评论:0      收藏:0      [点我收藏+]

标签:os   io   for   问题   re   c   

问题描述:

Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Determine if you are able to reach the last index.
For example:
A = [2,3,1,1,4], return true.
A = [3,2,1,0,4], return false.

class Solution {
public:
    bool canJump(int A[], int n) {
        if (n < 1) 
            return false;
        int max_step, i, tmp;
        max_step = tmp = 0;
        for (i = 0; i < n; i++) {
            if (A[i] > max_step)
                max_step = A[i];
            if ((tmp = max_step + i) == n-1 || tmp > n-1)
                return true;
            if (max_step == 0)
                return false;
            max_step--;
        }
    }
};


Leet code —Jump Game,布布扣,bubuko.com

Leet code —Jump Game

标签:os   io   for   问题   re   c   

原文地址:http://blog.csdn.net/wan_hust/article/details/38048337

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