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状态表示要明确,无论G和B的位置怎样。之后的情况仅仅和B与G的数量有关。所以能够DP。DP[i][j]表示如今中了i个B植物,j个G植物的总伤害。能够贪心。实现採用一维DP处理
LL n, g, b, r, t;
LL dp[MAXN];
int main()
{
int T;
RI(T);
FE(kase, 1, T)
{
cin >> n >> r >> g >> b >> t;
LL ans = n * r * t;
CLR(dp, -1); dp[0] = 0;
REP(all, n)
{
FED(i, n, 0)
{
if (~dp[i])
{
LL nxt = dp[i] + (i * b + t) * (all - i) * g;
if (dp[i + 1] < nxt)
dp[i + 1] = nxt;
nxt = dp[i] + (i * b + t) * (all - i) * g;
if (dp[i] < nxt)
dp[i] = nxt;
}
}
FE(i, 0, n)
{
if (~dp[i])
{
LL nxt = dp[i] + (n - all - 1) * (t + i * b) * (r + (all + 1 - i) * g);
if (ans < nxt)
ans = nxt;
}
}
}
printf("Case #%d: %I64d\n", kase, ans);
}
return 0;
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原文地址:http://www.cnblogs.com/mengfanrong/p/5109939.html