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servlet过滤器

时间:2016-01-09 21:30:28      阅读:145      评论:0      收藏:0      [点我收藏+]

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servlet的过滤器解决了是否登录状态问题。

1.创建一个AccessFilter类,基础代码

package valid.filter;

import java.io.IOException;

import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class AccessFilter implements Filter{
    public void destroy() {
        System.out.println("请求销毁");
    }
    @Override
    public void doFilter(ServletRequest res, ServletResponse rep,
            FilterChain chain) throws IOException, ServletException {
        HttpServletRequest request = (HttpServletRequest) res;
        HttpServletResponse response = (HttpServletResponse) rep;
        
        String requestURI = request.getRequestURI();
        String path = request.getContextPath();
        
        if(requestURI.startsWith(path + "/servlet/valServlet")){
            chain.doFilter(res, rep);
        }
        else{
            //这个时候,就说明需要判断权限了
            Object user = request.getSession().getAttribute("login");
            if(null == user){
                response.sendRedirect("../index.jsp");
            }else{
                chain.doFilter(res, rep);
            }
        }
        //放行
    }
    public void init(FilterConfig arg0) throws ServletException {
        System.out.println("请求初始化");
    }

}

2.web.xml配置

<filter>
     <filter-name>acess</filter-name>
     <filter-class>valid.filter.AccessFilter</filter-class>
 </filter>
 <filter-mapping>
     <filter-name>acess</filter-name>
     <url-pattern>/servlet/*</url-pattern>
 </filter-mapping>

所有servlet请求,都会先经过AccessFilter,只要没有登录状态,都将会被拦截,并跳转到首页

servlet过滤器

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原文地址:http://www.cnblogs.com/angto64/p/5117066.html

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