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1
#import <Foundation/Foundation.h> int main(int argc, const char * argv[]) { @autoreleasepool { NSSet *set=[NSSet set]; NSSet *set1=[NSSet setWithObjects:@"jack",@"rose",nil]; //存取数据的个数 NSInteger count=[set1 count]; NSLog(@"%ld",count); //随机拿取元素 NSString *str=[set1 anyObject]; NSLog(@"%@",str); //通过数组创建集合 NSArray *arr=[NSArray arrayWithObjects:@"jack",@"rose",@"2", @"9",@"3",nil]; NSSet *set2=[[NSSet alloc]initWithArray:arr]; //集合中是否包含内容为“1”这个字符串对象 BOOL result =[set2 containsObject:@"7"]; NSLog(@"%d",result); //判断两个集合是否含有相同的元素 BOOL result1=[set1 intersectsSet:set2]; NSLog(@"%d",result1); //集合1是否是集合2的子集合 BOOL result2=[set1 isSubsetOfSet:set2]; NSLog(@"%d",result2); } return 0; }
2
#import <Foundation/Foundation.h> int main(int argc, const char * argv[]) { @autoreleasepool { NSMutableSet *set1=[NSMutableSet set]; NSMutableSet *set2=[NSMutableSet setWithObjects:@"1",@"2",nil]; NSMutableSet *set3=[NSMutableSet setWithObjects:@"a",@"2" ,nil]; //集合2减去集合3中元素,最后集合2中的元素只剩1个,值为1; NSLog(@"%@",set2); NSLog(@"%@",set3); //[set2 minusSet:set3]; //NSLog(@"%@",set2); // NSLog(@"%@",set3); //集合2与集合3交集,最后集合2中的元素只有1个,值为2 // [set2 intersectSet:set3]; // NSLog(@"%@",set2); // NSLog(@"%@",set3); //集合2与结合3并集,最后集合2中的元素只有3个 1,2,a [set2 unionSet:set3]; NSLog(@"%@",set2); NSLog(@"%@",set3); [set2 removeObject:@"2"]; NSLog(@"%@",set2); [set1 setSet:set2]; NSLog(@"%@",set1); } return 0; }
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原文地址:http://www.cnblogs.com/hezhuangzhuang/p/5121744.html