1327-Undeclared variable:amount

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1、错误描述

2、错误原因

BEGIN
	SELECT stuAge INTO amount;
  IF stuAge IS NOT NULL THEN
  SET stuAge = stuAge + 1;
  SELECT stuAge INTO amount1;
  ELSE
  SELECT 20 INTO amount2;
  END IF;
  SELECT stuAge INTO amount3;
END;

   amount实际是stuAge的别名，但是却写成了一个变量

3、解决办法

BEGIN
	SELECT stuAge AS amount;
  IF stuAge IS NOT NULL THEN
  SET stuAge = stuAge + 1;
  SELECT stuAge AS amount1;
  ELSE
  SELECT 20 INTO stuAge;
  END IF;
  SELECT stuAge AS amount3;
END

1327-Undeclared variable:amount

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原文地址：http://blog.csdn.net/you23hai45/article/details/50499052