[?]*Maximum Size Subarray Sum Equals k

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Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn‘t one, return 0 instead.

Example 1:

Given nums = [1, -1, 5, -2, 3], k = 3,
return 4. (because the subarray [1, -1, 5, -2] sums to 3 and is the longest)

Example 2:

Given nums = [-2, -1, 2, 1], k = 1,
return 2. (because the subarray [-1, 2] sums to 1 and is the longest)

Follow Up:
Can you do it in O(n) time?

public int maxSubArrayLen(int[] nums, int k) {
    int sum = 0, max = 0;
    HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
    for (int i = 0; i < nums.length; i++) {
        sum = sum + nums[i];
        if (sum == k) max = i + 1;
        else if (map.containsKey(sum - k)) max = Math.max(max, i - map.get(sum - k));
        if (!map.containsKey(sum)) map.put(sum, i);
    }
    return max;
}

[?]*Maximum Size Subarray Sum Equals k

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原文地址：http://www.cnblogs.com/hygeia/p/5123140.html