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It‘s the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena‘s code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from each country, find their product. If it is turns to be too large, then the servers might have not enough time to assign tanks into teams and the whole game will collapse!
There are exactly n distinct countries in the world and the i-th country added ai tanks to the game. As the developers of the game are perfectionists, the number of tanks from each country is beautiful. A beautiful number, according to the developers, is such number that its decimal representation consists only of digits ‘1‘ and ‘0‘, moreover it contains at most one digit ‘1‘. However, due to complaints from players, some number of tanks of one country was removed from the game, hence the number of tanks of this country may not remain beautiful.
Your task is to write the program that solves exactly the same problem in order to verify Gena‘s code correctness. Just in case.
The first line of the input contains the number of countries n (1 ≤ n ≤ 100 000). The second line contains n non-negative integers aiwithout leading zeroes — the number of tanks of the i-th country.
It is guaranteed that the second line contains at least n - 1 beautiful numbers and the total length of all these number‘s representations doesn‘t exceed 100 000.
Print a single number without leading zeroes — the product of the number of tanks presented by each country.
3
5 10 1
50
4
1 1 10 11
110
5
0 3 1 100 1
0
水题啦不过要注意一些细节 比如对0的处理 比如...好像没什么了啊...
#include <iostream> #include <string> #include <cstdio> #include <cmath> #include <cstring> #include <queue> #include <map> #include <vector> #include <set> #include <algorithm> #define INF 0x3F3F3F3F using namespace std; bool isBeautiful(char data[]){ int len = strlen(data); if(data[0] != ‘1‘) return false; for(int i = 1; i < len; i++){ if(data[i] != ‘0‘) return false; } return true; } int main() { int n, digit = 0; char data[100010], nonb[100010] = "1"; bool zero = false; scanf("%d", &n); while(n--){ scanf("%s", data); if(data[0] == ‘0‘) zero = true; if(isBeautiful(data)) digit += strlen(data) - 1; else strcpy(nonb, data); } if(zero) puts("0"); else{ printf("%s", nonb); for(int i = 1; i <= digit; i++) printf("0"); putchar(‘\n‘); } return 0; } close
Codeforces Round #339 Div.2 B - Gena's Code
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原文地址：http://www.cnblogs.com/quasar/p/5132183.html
