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GCD
Input: Standard Input

Output: Standard Output

Given the value of N, you will have to find the value of G. The definition of G is given below:

Here GCD(i,j) means the greatest common divisor of integer i and integer j.

For those who have trouble understanding summation notation, the meaning of G is given in the following code:

Input

The input file contains at most 100 lines of inputs. Each line contains an integer N (1<N<501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero.  This zero should not be processed.

Output

For each line of input produce one line of output. This line contains the value of G for corresponding N.

Sample Input                              Output for Sample Input

Problemsetter: Shahriar Manzoor

Special Thanks: Syed Monowar Hossain

 1 #include<iostream>
 2 #include<stdio.h>
 3 #include<cstring>
 4 #include<cstdlib>
 5 using namespace std;
 6 const int maxn = 503;
 7 
 8 int G[maxn];
 9 int opl[maxn];
10 void init()
11 {
12     int i,j;
13     memset(G,0,sizeof(G));
14     for(i=2;i<maxn;i++) opl[i] = i;
15     for(i=2;i<maxn;i++)
16     {
17         if(opl[i]==i)
18         {
19             for(j=i;j<maxn;j=j+i)
20                 opl[j] = opl[j]/i*(i-1);
21         }
22         for(j=1;i*j<maxn;j++)/**opl [ i  ] 此时已经算出**/
23             G[j*i] = G[j*i] + opl[i]*j;
24     }
25     for(i=3;i<maxn;i++)
26         G[i] +=G[i-1];
27 }
28 int main()
29 {
30     int n;
31     init();
32     while(scanf("%d",&n)>0)
33     {
34         if(n==0)break;
35         printf("%d\n",G[n]);
36     }
37     return 0;
38 }

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uva 11417 - GCD

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原文地址：http://www.cnblogs.com/tom987690183/p/3862795.html