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Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
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方法：用矩阵中的某一零行来记录零列的信息
过程如下：
1.从下往上遍历矩阵，找到第一个0元素，我们将其所在行作为记录行，用它来记录列号
2.接着从上向下遍历矩阵，找到0元素，将其所在行赋值为0，并在记录行中同列的元素赋值为0，作为记录
3.根据记录行中的记录，将0元素所在的列全部赋值为0
4.将记录行赋值为0
void setZeroes(vector<vector<int>>& matrix) { const int h = matrix.size(); const int w = matrix[0].size(); int store = -1; for (int i = h - 1; i >= 0; --i) { if (store != -1) break; for (int j = 0; j < w; ++j) { if (matrix[i][j] == 0) { store = i; break; } } } if (store == -1) return; for (int i = 0; i < store; ++i) { bool isZero = false; for (int j = 0; j < w; ++j) { if (matrix[i][j] == 0) { matrix[store][j] = 0; isZero = true; } } if (isZero) for (int j = 0; j < w; ++j) matrix[i][j] = 0; } for (int j = 0; j < w; ++j) if(matrix[store][j] == 0) for (int i = 0; i < h; ++i) matrix[i][j] = 0; for (int j = 0; j < w; ++j) matrix[store][j] = 0; }
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原文地址：http://www.cnblogs.com/sdlwlxf/p/5134581.html
