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二叉树的镜像定义:源二叉树 8 / 6 10 / \ / 5 7 9 11 镜像二叉树 8 / 10 6 / \ / 11 9 7 5
1 /* 2 struct TreeNode { 3 int val; 4 struct TreeNode *left; 5 struct TreeNode *right; 6 TreeNode(int x) : 7 val(x), left(NULL), right(NULL) { 8 } 9 };*/ 10 class Solution { 11 public: 12 void Mirror(TreeNode *pRoot) { 13 if (pRoot == NULL) 14 return ; 15 if (pRoot->left != NULL) 16 Mirror(pRoot->left); 17 if (pRoot->right != NULL) 18 Mirror(pRoot->right); 19 TreeNode *ptem = pRoot->left; 20 pRoot->left = pRoot->right; 21 pRoot->right = ptem; 22 } 23 };
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原文地址:http://www.cnblogs.com/xiaoyesoso/p/5149519.html