1.22 P235第三题创建Map集合，创建Emp对象，将Emp对象添加到集合中，并将id为005的对象从集合中移除。

 1 public static void main(String[] args) {
 2         
 3         HashMap<String,String> map = new HashMap<String,String>(); //创建集合map
 4         
 5         Emp  e1 = new Emp("001","星期一");
 6         Emp  e2 = new Emp("002","星期二");
 7         Emp  e3 = new Emp("003","星期三");
 8         Emp  e4 = new Emp("004","星期四");
 9         Emp  e5 = new Emp("005","星期五");
10         Emp  e6 = new Emp("006","星期六");
11         Emp  e7 = new Emp("007","星期日");
12         
13         map.put(e1.getId(), e1.getName());
14         map.put(e2.getId(), e2.getName());
15         map.put(e3.getId(), e3.getName());
16         map.put(e4.getId(), e4.getName());
17         map.put(e5.getId(), e5.getName());
18         map.put(e6.getId(), e6.getName());
19         map.put(e7.getId(), e7.getName());
20         
21         System.out.print("数组1 ：");
22         System.out.println(" " + map);    //输出
23         
24         map.remove("005");
25         System.out.print("数组2 ：");
26         System.out.println(" "+ map);     //输出
27         
28     }    
29 }
30 class Emp{
31     
32     private String id;
33     private String name;
34     
35     public Emp(String id, String name) {  //构造函数
36         //super();
37         
38         this.id = id;
39         this.name = name;
40     }
41 
42     public String getId() {              //getter setter方法
43         return id;
44     }
45 
46     public void setId(String id) {
47         this.id = id;
48     }
49 
50     public String getName() {
51         return name;
52     }
53 
54     public void setName(String name) {
55         this.name = name;
56     }
57