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Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
太水了,就是简单的位运算,只要想到一个简单的策略就好了
Ps.由于java对无符号数支持不好,所以这里就用c水过就好啦。
#include <stdio.h> #include <inttypes.h> uint32_t reverseBits(uint32_t n) { uint32_t ret = 0; for(int i=0 ;i<=31;i++){ ret+=((n & (1<<i))>>i)<< (31-i); } return ret; } int main(){ uint32_t n; scanf("%d",&n); printf("%u",reverseBits(n)); return 0; }
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原文地址:http://www.cnblogs.com/dick159/p/5157392.html