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题1:BZOJ1854 SCOI2010游戏
每个属性x,y分别向i连条边,匹配到不能匹配为止。
输出即可。
1 #include <cstdio> 2 #include <cstring> 3 #include <cstdlib> 4 #include <iostream> 5 #include <algorithm> 6 7 using namespace std; 8 9 const int N = 1000000 + 5; 10 11 int tim = 0, n, tot = 0; 12 int first[N], next[N<<1]; 13 int u[N<<1], v[N<<1]; 14 int used[N], girl[N]; 15 16 void Add(int s, int t){ 17 ++ tot; 18 u[tot] = s; v[tot] = t; 19 next[tot] = first[u[tot]]; 20 first[u[tot]] = tot; 21 } 22 23 bool find(int now){ 24 for(int i = first[now]; i; i = next[i]){ 25 if(used[v[i]] != tim){ 26 used[v[i]] = tim; 27 28 if(girl[v[i]] == 0 || find(girl[v[i]])){ 29 girl[v[i]] = now; 30 return true; 31 } 32 } 33 } 34 35 return false; 36 } 37 38 #define ONLINE_JUDGE 39 int main(){ 40 #ifndef ONLINE_JUDGE 41 freopen("game.in", "r", stdin); 42 freopen("game.out", "w", stdout); 43 #endif 44 45 int x, y; 46 47 scanf("%d", &n); 48 for(int i = 1; i <= n; ++ i){ 49 scanf("%d%d", &x, &y); 50 Add(x, i); Add(y, i); 51 } 52 53 int ans = 0; 54 for(int i = 1; i <= 10000; ++ i){ 55 ++ tim; 56 if(find(i)) 57 ++ ans; 58 else break; 59 } 60 61 printf("%d\n", ans); 62 63 #ifndef ONLINE_JUDGE 64 fclose(stdin); fclose(stdout); 65 #endif 66 return 0; 67 }
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原文地址:http://www.cnblogs.com/sxprovence/p/5161589.html