码迷,mamicode.com
首页 > 其他好文 > 详细

[LeetCode] Symmetric Tree

时间:2014-07-24 10:04:33      阅读:214      评论:0      收藏:0      [点我收藏+]

标签:style   blog   color   strong   io   for   

Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).

For example, this binary tree is symmetric:

    1
   /   2   2
 / \ / 3  4 4  3

 

But the following is not:

    1
   /   2   2
   \      3    3

 

Note: Bonus points if you could solve it both recursively and iteratively.

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSymmetric(TreeNode *root) {
        if(root == NULL)
            return true;
        TreeNode *pleft = root->left;
        TreeNode *pright = root->right;
        return isMirror(pleft,pright);
        
    }
private:
    bool isMirror(TreeNode *pleft,TreeNode *pright){
        if(pleft==NULL && pright==NULL)
            return true;
        if((pleft==NULL && pright!=NULL)||(pleft!=NULL && pright==NULL))
            return false;
        else if(pleft->val != pright->val)
            return false;
        else if(isMirror(pleft->left,pright->right)==false || isMirror(pleft->right,pright->left)==false)
            return false;
        else
            return true;
    
    
    }
};

[LeetCode] Symmetric Tree,布布扣,bubuko.com

[LeetCode] Symmetric Tree

标签:style   blog   color   strong   io   for   

原文地址:http://www.cnblogs.com/Xylophone/p/3864706.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!