标签:des style java color os io for re
2 3 2 1 2 1 2 3 1 3 3 1 2 1 2 3 1 1 3 1
Case 1: 1 Case 2: 2
题意:n个节点,m条路径,其中给出每条路径的容量。求1到n的最大流
<span style="font-size:24px;">#include<stdio.h>
#include<algorithm>
#include<queue>
#define INF 1000
#define min(x,y) (x<y?x:y)
using namespace std;
int cap[20][20],flow[20][20],a[1000],p[100];
int n,m,f,s,t;
void Edmonds_Karp()
{
queue<int> q;
memset(flow,0,sizeof(flow));
f=0;
s=1;
t=n;
while(1)
{
memset(a,0,sizeof(a));
a[s]=INF;
q.push(s);
while(!q.empty())
{
int u=q.front();
q.pop();
for(int v=1;v<=n;v++)
{
if(!a[v]&&cap[u][v]>flow[u][v])
{
p[v]=u;
q.push(v);
a[v]=min(a[u],cap[u][v]-flow[u][v]);
}
}
}
if(a[t]==0) break;
for(int u=t;u!=s;u=p[u])
{
flow[p[u]][u]+=a[t];
flow[u][p[u]]-=a[t];
}
f+=a[t];
}
}
int main()
{
int t,k=1;
scanf("%d",&t);
while(t--)
{
scanf("%d %d",&n,&m);
memset(cap,0,sizeof(cap));
for(int i=0;i<m;i++)
{
int x,y,c;
scanf("%d %d %d",&x,&y,&c);
cap[x][y]+=c;
}
Edmonds_Karp();
printf("Case %d: %d\n",k++,f);
}
return 0;
}</span>hdu 3549 Flow Problem,布布扣,bubuko.com
标签:des style java color os io for re
原文地址:http://blog.csdn.net/fyxz1314/article/details/38082443