标签:des style java color os io for re
2 3 2 1 2 1 2 3 1 3 3 1 2 1 2 3 1 1 3 1
Case 1: 1 Case 2: 2
题意:n个节点,m条路径,其中给出每条路径的容量。求1到n的最大流
<span style="font-size:24px;">#include<stdio.h> #include<algorithm> #include<queue> #define INF 1000 #define min(x,y) (x<y?x:y) using namespace std; int cap[20][20],flow[20][20],a[1000],p[100]; int n,m,f,s,t; void Edmonds_Karp() { queue<int> q; memset(flow,0,sizeof(flow)); f=0; s=1; t=n; while(1) { memset(a,0,sizeof(a)); a[s]=INF; q.push(s); while(!q.empty()) { int u=q.front(); q.pop(); for(int v=1;v<=n;v++) { if(!a[v]&&cap[u][v]>flow[u][v]) { p[v]=u; q.push(v); a[v]=min(a[u],cap[u][v]-flow[u][v]); } } } if(a[t]==0) break; for(int u=t;u!=s;u=p[u]) { flow[p[u]][u]+=a[t]; flow[u][p[u]]-=a[t]; } f+=a[t]; } } int main() { int t,k=1; scanf("%d",&t); while(t--) { scanf("%d %d",&n,&m); memset(cap,0,sizeof(cap)); for(int i=0;i<m;i++) { int x,y,c; scanf("%d %d %d",&x,&y,&c); cap[x][y]+=c; } Edmonds_Karp(); printf("Case %d: %d\n",k++,f); } return 0; }</span>
hdu 3549 Flow Problem,布布扣,bubuko.com
标签:des style java color os io for re
原文地址:http://blog.csdn.net/fyxz1314/article/details/38082443