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Please note: VROOK cannot go back-ward - that leads to a simple variation to Game of Nim: just XOR.
t = int(input()) for _ in range(t): n = int(input()) # Get input p1 = [] for _ in range(n): p1.append(int(input())) p2 = [] for _ in range(n): p2.append(int(input())) # Game of Nim nim = 0 for i in range(n): nim ^= abs(p2[i]- p1[i]) - 1 print ("player-2" if nim != 0 else "player-1")
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原文地址：http://www.cnblogs.com/tonix/p/5186290.html
