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1 #include<iostream> 2 #include<string> 3 #include<algorithm> 4 #include<cstdlib> 5 #include<cstdio> 6 #include<set> 7 #include<map> 8 #include<vector> 9 #include<cstring> 10 #include<stack> 11 #include<cmath> 12 #include<queue> 13 //#include <bits/stdc++.h> 14 using namespace std; 15 #define LL long long 16 const int maxn=100000; 17 struct node 18 { 19 LL sum,val; 20 }tree[maxn*4]; 21 22 void pushup(int rt) 23 { 24 tree[rt].sum=tree[rt<<1].sum+tree[rt<<1|1].sum; 25 } 26 void pushdown(int rt,int m) 27 { 28 if(tree[rt].val) 29 { 30 tree[rt<<1].val+=tree[rt].val; 31 tree[rt<<1|1].val+=tree[rt].val; 32 tree[rt<<1].sum+=(LL)(m-(m>>1))*tree[rt].val; 33 tree[rt<<1|1].sum+=(LL)(m>>1)*tree[rt].val; 34 tree[rt].val=0; 35 } 36 } 37 38 void build_tree(int l,int r,int rt) 39 { 40 tree[rt].val=0; 41 if(l==r) 42 { 43 scanf("%I64d",&tree[rt].sum); 44 return ; 45 } 46 int m=(l+r)>>1; 47 build_tree(l,m,rt<<1); 48 build_tree(m+1,r,rt<<1|1); 49 pushup(rt); 50 } 51 52 LL query(int L,int R,int l,int r,int rt) 53 { 54 if(L<=l&&r<=R) 55 { 56 return tree[rt].sum; 57 } 58 int m=(l+r)>>1; 59 pushdown(rt,r-l+1); 60 LL ans=0; 61 if(L<=m) 62 ans+=query(L,R,l,m,rt<<1); 63 if(m<R) 64 ans+=query(L,R,m+1,r,rt<<1|1); 65 pushup(rt); 66 return ans; 67 } 68 69 void update(int L,int R,int add,int l,int r,int rt) 70 { 71 if(L<=l&&r<=R) 72 { 73 tree[rt].sum+=(LL)add*(r-l+1); 74 tree[rt].val+=add; 75 return; 76 } 77 pushdown(rt,r-l+1); 78 int m=(l+r)>>1; 79 if(L<=m) 80 update(L,R,add,l,m,rt<<1); 81 if(R>m) 82 update(L,R,add,m+1,r,rt<<1|1); 83 pushup(rt); 84 } 85 86 int main() 87 { 88 int n,a,b,q; 89 LL c; 90 while(~scanf("%d%d",&n,&q)) 91 { 92 build_tree(1,n,1); 93 char s[3]; 94 while(q--) 95 { 96 scanf("%s",s); 97 if(s[0]==‘Q‘) 98 { 99 cin>>a>>b; 100 cout<<query(a,b,1,n,1)<<endl; 101 } 102 else if(s[0]==‘C‘) 103 { 104 cin>>a>>b>>c; 105 update(a,b,c,1,n,1); 106 } 107 } 108 } 109 return 0; 110 }
POJ 3468 A Simple Problem with Integers 线段树 区间更新
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原文地址:http://www.cnblogs.com/ITUPC/p/5202534.html