lintcode-easy-Majority Number

public class Solution {
    /**
     * @param nums: a list of integers
     * @return: find a  majority number
     */
    public int majorityNumber(ArrayList<Integer> nums) {
        // write your code
        if(nums == null || nums.size() == 0)
            return 0;
        
        Integer result = null;
        int count = 0;
        
        for(int i = 0; i < nums.size(); i++){
            if(result == null){
                result = nums.get(i);
                count = 1;
            }
            else if(nums.get(i) == result){
                count++;
            }
            else{
                count--;
                if(count == 0){
                    result = nums.get(i);
                    count = 1;
                }
            }
        }
        
        return result;
    }
}