标签:
题目:
Reverse a singly linked list.
cpp:
class Solution { public: ListNode* reverseList(ListNode* head) { if(!head || !head->next) return head; ListNode *p1 = head; ListNode *p2 = head->next; ListNode *p3 = head->next->next; p1->next = nullptr; while(p3){ p2->next = p1; p1 = p2; p2 = p3; p3 = p3->next; } p2->next = p1; return p2; } };
python:
class Solution(object): def reverseList(self,head): if not head or not head.next: return head; p1,p2,p3 = head,head.next,head.next.next p1.next = None while p3: p2.next = p1 p1 = p2 p2 = p3 p3 = p3.next p2.next = p1 return p2
标签:
原文地址:http://www.cnblogs.com/wxquare/p/5223811.html