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Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.
You may assume that the array is non-empty and the majority element always exist in the array.
解题思路:
思路请看剑指offer的面试29.。。。。。
class Solution { public: int majorityElement(vector<int>& nums) { int n=nums.size(); if(n==1)return nums[0]; int pre=nums[0]; int cnt=1; for(int i=0;i<n;i++){ if(nums[i]==pre)cnt++; else cnt--; if(cnt==0){ pre=nums[i]; cnt=1; } } return pre; } }; |
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原文地址:http://www.cnblogs.com/olivelv/p/5235679.html