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【leetcode刷题笔记】Insert Interval

时间:2014-07-26 00:37:46      阅读:237      评论:0      收藏:0      [点我收藏+]

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Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

You may assume that the intervals were initially sorted according to their start times.

Example 1:
Given intervals [1,3],[6,9], insert and merge [2,5] in as [1,5],[6,9].

Example 2:
Given [1,2],[3,5],[6,7],[8,10],[12,16], insert and merge [4,9] in as [1,2],[3,10],[12,16].

This is because the new interval [4,9] overlaps with [3,5],[6,7],[8,10].

 


题解:利用变量insertPos记录最终区间插入的位置。遍历intervals,那么当前遍历的interval和newInterval有以下几种情况:

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代码如下:

 1 /**
 2  * Definition for an interval.
 3  * public class Interval {
 4  *     int start;
 5  *     int end;
 6  *     Interval() { start = 0; end = 0; }
 7  *     Interval(int s, int e) { start = s; end = e; }
 8  * }
 9  */
10 public class Solution {
11     public List<Interval> insert(List<Interval> intervals, Interval newInterval) {
12         List<Interval> answer = new ArrayList<Interval>();
13         int insertPos = 0;
14         for(Interval in:intervals){
15             if(newInterval.start > in.end){
16                 answer.add(in);
17                 insertPos++;
18             }
19             else if(in.start > newInterval.end)
20             {
21                 answer.add(in);
22             }
23             else{
24                 newInterval.start = Math.min(in.start, newInterval.start);
25                 newInterval.end = Math.max(in.end, newInterval.end);
26             }            
27         }
28         answer.add(insertPos, newInterval);
29         return answer;
30     }
31 }

【leetcode刷题笔记】Insert Interval,布布扣,bubuko.com

【leetcode刷题笔记】Insert Interval

标签:style   blog   http   color   os   strong   io   2014   

原文地址:http://www.cnblogs.com/sunshineatnoon/p/3868589.html

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