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http://poj.org/problem?id=2891
解线性模方程组。
比较坑爹,数据比较大,很容易溢出。
1 Program poj2891; 2 3 var m:int64; 4 5 a,r:array[1..30000000]of int64; 6 7 ans,x,y,lcm:int64; 8 9 10 Procedure init; 11 12 var i,j:longint; 13 14 begin 15 16 m:=0; 17 18 readln(m); 19 20 for i:=1 to m do 21 22 readln(a[i],r[i]); 23 24 end; 25 26 27 Function extended_gcd(a,b:int64;var x,y:int64):int64; 28 29 var k:int64; 30 31 begin 32 33 if b=0 then begin 34 35 extended_gcd:=a; 36 37 x:=1;y:=0; 38 39 end 40 41 else begin 42 43 extended_gcd:=extended_gcd(b,a mod b,x,y); 44 45 k:=x;x:=y;y:=k-(a div b)*y; 46 47 end; 48 49 end; 50 51 52 Procedure print(ans:int64); 53 54 begin 55 56 writeln(ans); 57 58 end; 59 60 61 Procedure main; 62 63 var i:longint; 64 65 d,ai,ri,k:int64; 66 67 begin 68 69 ans:=0; 70 71 ai:=a[1];ri:=r[1]; 72 73 for i:=2 to m do 74 75 begin 76 77 d:=extended_gcd(ai,a[i],x,y); 78 79 lcm:=a[i]*ai div d; 80 81 if (r[i]-ri)mod d<>0 then begin print(-1);exit;end; 82 83 k:=((x mod a[i])*(r[i]-ri) mod a[i])div d; //这个取余很重要,没有的话就会溢出,在这wa了好久 84 85 ri:=((ri+ai*k) mod lcm+lcm)mod lcm; 86 87 ai:=lcm; 88 89 end; 90 91 print(ri); 92 93 end; 94 95 96 Begin 97 98 assign(input,‘input.in‘);reset(input); 99 100 assign(output,‘output.out‘);rewrite(output); 101 102 while not(eof) do 103 104 begin 105 106 init; 107 108 if m<>0 then main; 109 110 end; 111 112 close(Input);close(Output); 113 114 end.
poj 2891 Strange Way to Express Integers 2012-09-05
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原文地址:http://www.cnblogs.com/yesphet/p/5236495.html