对二进制加密（分散保存-s=sy+a+b）

  1 #include <stdio.h>
  2 #define L 40
  3 void jiaM(int * s,int * a,int *b,int *sy);
  4 void jieM(int * a,int *b,int *sy);
  5 int main()
  6 {
  7     int s[L]={1,1,1,0,0,1,0,1,0,0,0,1,0,0,1,1,0,0,1,1,1,1,0,0,1,0,1,0,0,0,1,0,0,1,1,0,0,1,1,0};
  8 //    int s[L]={1,0,1,1,1,0,0,1,1,0,0,0,0,1,1,0,0,0,0,0};
  9     int a[L/2],b[L/2],sy[L/2];
 10     jiaM(s,a,b,sy);
 11     jieM(a,b,sy);
 12     printf("\n");
 13     return 0;
 14 }
 15 void jiaM(int * s,int * a,int *b,int *sy)
 16 {
 17     int i=0,j=1,k=0;
 18     for(;i<L;i+=2,j+=2)
 19     {
 20         if(s[i]!=s[j]){sy[k++]=1;}
 21             else{sy[k++]=0;}
 22     }
 23 
 24     for(i=0;i<L;i++)
 25     {printf("%d",s[i]);}
 26     printf("----´òÓ¡Ô´----\n");
 27 
 28     for(i=0;i<L/2;i++)
 29     {printf("%d ",sy[i]);}
 30     printf("----´òÓ¡sy----\n");
 31     
 32     int a1=0,b1=0;
 33     for(k=0,i=0,j=1;i<L;i+=2,j+=2)
 34     {
 35         if(sy[k++])
 36         {
 37             if(s[i]!=0)
 38             {
 39                 b[b1++]=1;
 40             }else
 41             {
 42                 b[b1++]=0;
 43             }
 44         }
 45         else
 46         {
 47             if(s[i]!=0)
 48             {
 49                 a[a1++]=1;
 50             }else
 51             {
 52                 a[a1++]=0;
 53             }
 54         }
 55     }
 56 
 57     for(i=0;i<L/2;i++)
 58     {if(a[i]==0||a[i]==1)printf("%d ",a[i]);}
 59     printf("----´òÓ¡a----\n");
 60 
 61     for(i=0;i<L/2;i++)
 62     {if(b[i]==0||b[i]==1)printf("%d ",b[i]);}
 63     printf("----´òÓ¡b----\n");
 64 
 65 
 66 }
 67 
 68 void jieM(int * a,int *b,int *sy)
 69 {
 70     int s[L],l=0,m=1,x=0,y=0,k,j;
 71     for(k=0,j=0;k<L/2;k++,l+=2,m+=2)
 72     {
 73         if(sy[k])
 74         {
 75             if(b[x++])
 76             {
 77                 s[l]=1;
 78                 s[m]=0;
 79             }
 80             else
 81             {
 82                 s[l]=0;
 83                 s[m]=1;
 84             }
 85         }
 86         else
 87         {
 88             if(a[y++])
 89             {
 90                 s[l]=1;
 91                 s[m]=1;
 92             }
 93             else
 94             {
 95                 s[l]=0;
 96                 s[m]=0;
 97             }
 98         }    
 99     }
100     
101     for(j=0;j<L;j++)
102     {
103         printf("%d",s[j]);
104     }
105 }