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敌兵布阵

1
10
1 2 3 4 5 6 7 8 9 10
Query 1 3
Add 3 6
Query 2 7
Sub 10 2
Add 6 3
Query 3 10
End 

Case 1:
6
33
59

#include<stdio.h>
#include<string.h>
#include<iostream>
using namespace std;
struct Node{
    int left,right;
    int s;
}a[200010];
void built(int cur,int x,int y){
    a[cur].left=x; a[cur].right=y;
    if(x==y){
        scanf("%d",&a[cur].s);
        return ;
    }
    if(x<y){
        int mid=(x+y)>>1;
        built(cur<<1,x,mid);
        built(cur<<1 |1,mid+1,y);
        a[cur].s=a[cur<<1].s+a[cur<<1|1].s;
    }
}
void insert(int cur,int v,int val){
    if(a[cur].left==v && a[cur].right==v){
        a[cur].s+=val;
        return ;
    }
    int mid=(a[cur].left+a[cur].right)>>1;
    if(v<=mid)
        insert(cur<<1,v,val);
    else
        insert(cur<<1 | 1,v,val);
    a[cur].s=a[cur<<1].s+a[cur<<1 | 1].s;
}
int sum(int cur,int x,int y){
    if(a[cur].left==x && a[cur].right==y)
        return a[cur].s;
    int mid=(a[cur].left+a[cur].right)>>1;
    if(y<=mid)
        return sum(cur<<1,x,y);
    else if(x>mid)
        return sum(cur<<1|1,x,y);
    else{
        return sum(cur<<1,x,mid)+sum(cur<<1|1,mid+1,y);
    }
}
//void output(int cur){
//    if(a[cur].left==a[cur].right){
//        printf("%d ",a[cur].s);
//        return ;
//    }
//    output(cur<<1);
//    output(cur<<1 | 1);
//}
int main(){
    int T; scanf("%d",&T);
    for(int cas=1;cas<=T;cas++){
        printf("Case %d:\n",cas);
        int n; 
        char ch[10];
        scanf("%d",&n);
        built(1,1,n);
        while(1){
            scanf("%s",ch);
            if(!strcmp("Query",ch)){
                int x,y;
                scanf("%d%d",&x,&y);
                printf("%d\n",sum(1,x,y));
            }
            else if(!strcmp("Add",ch)){
                int x,y;
                scanf("%d%d",&x,&y);
                insert(1,x,y);
            }
            else if(!strcmp("Sub",ch)){
                int x,y;
                scanf("%d%d",&x,&y);
                insert(1,x,-y);
            }
            else
                break;
        }
    }
    return 0;
}

hdu 1166,布布扣,bubuko.com

hdu 1166

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原文地址：http://blog.csdn.net/my_acm/article/details/38112583