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LeetCode-Increasing Triplet Subsequence

时间:2016-03-11 07:46:46      阅读:192      评论:0      收藏:0      [点我收藏+]

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Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.

Formally the function should:
Return true if there exists i, j, k 
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false.
Your algorithm should run in O(n) time complexity and O(1) space complexity.

Examples:
Given [1, 2, 3, 4, 5],
return true.

Given [5, 4, 3, 2, 1],
return false.

 

 

public class Solution {
    public boolean increasingTriplet(int[] nums) {
        int a=Integer.MAX_VALUE;
        int b=Integer.MAX_VALUE;
        int len=nums.length;
        
        for(int i=0; i<len; i++){
            if(a >= nums[i]){
                a=nums[i];
            }
            else if(b >= nums[i]){
                b=nums[i];
            }
            else{
                return true;
            }
        }
        return false;
    }
}

 

LeetCode-Increasing Triplet Subsequence

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原文地址:http://www.cnblogs.com/incrediblechangshuo/p/5264182.html

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