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Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array. Formally the function should: Return true if there exists i, j, k such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false. Your algorithm should run in O(n) time complexity and O(1) space complexity. Examples: Given [1, 2, 3, 4, 5], return true. Given [5, 4, 3, 2, 1], return false.
public class Solution { public boolean increasingTriplet(int[] nums) { int a=Integer.MAX_VALUE; int b=Integer.MAX_VALUE; int len=nums.length; for(int i=0; i<len; i++){ if(a >= nums[i]){ a=nums[i]; } else if(b >= nums[i]){ b=nums[i]; } else{ return true; } } return false; } }
LeetCode-Increasing Triplet Subsequence
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原文地址:http://www.cnblogs.com/incrediblechangshuo/p/5264182.html