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For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
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public class Solution { public int threeSumClosest(int[] num, int target) { if(num == null || num.length<3) return 0; Arrays.sort(num); int closest = num[0]+num[1]+num[2]; for(int first = 0;first<num.length-2;++first) { if(first > 0 && num[first]==num[first-1]) continue; int second = first+1; int third = num.length -1; while(second<third) { int sum = num[first]+num[second]+num[third]; if(sum == target) return target; if(sum>target) --third; else ++second; if(Math.abs(closest-target)>Math.abs(sum-target)) closest = sum; } } return closest; } }
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原文地址:http://www.cnblogs.com/neweracoding/p/5267730.html