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Balanced Binary Tree:
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
tags:深度优先遍历
class Solution { private: //求出树的深度 int depth(TreeNode *root){ if(NULL == root) return 0; return max(depth(root->left), depth(root->right)) + 1; } public: bool isBalanced(TreeNode* root) { if(NULL == root) return true; //判断是否符合条件 if(abs(depth(root->left) - depth(root->right)) > 1) return false; //递归的判断左右子树是否是平衡的 return isBalanced(root->left) && isBalanced(root->right); } };
感觉这样做会重复计算了子树的深度,不过这样做思路比较清晰。
LeetCode题目:Balanced Binary Tree
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原文地址:http://www.cnblogs.com/runnyu/p/5275236.html