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#coding:utf-8
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折半查找返回值是mid+1
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def half_search(data,target):
low,high = 0,len(data)-1
while low<=high:
mid = (low+high)//2
if data[mid] == target:
return mid+1
elif data[mid] > target:
high = mid -1
else:
low = mid+1
return 0
data = [1,3,4,67,6]
target = 6
a=half_search(data,target)-1
print a
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原文地址:http://www.cnblogs.com/linbinqiang/p/5287482.html