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POJ1325_Machine Schedule(二分图/最小点覆盖=最大匹配)

时间:2014-07-26 17:14:22      阅读:253      评论:0      收藏:0      [点我收藏+]

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解题报告

http://blog.csdn.net/juncoder/article/details/38147135

题目传送门

题意:

A机器有n个模式,B机器有m个模式,每个作业可以在任何机器的特定模式下工作,转换模式需要耗时,求最小耗时

思路:

把AB两机器的模式当成二分图顶点,模式之间的连线就是某个作业可以在该两个模式下工作,就转换成求最小点覆盖,用最少的点覆盖最多的边。

最小点覆盖=最大匹配

#include <queue>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <iostream>
using namespace std;
int mmap[220][220],n,m,k,vis[220],pre[220];
int dfs(int x)
{
    int i;
    for(i=n;i<n+m;i++)
    {
        if(!vis[i]&&mmap[x][i])
        {
            vis[i]=1;
            if(pre[i]==-1||dfs(pre[i]))
            {
                pre[i]=x;
                return 1;
            }
        }
    }
    return 0;
}
int main()
{
    int i,j,a,x,y;
    while(cin>>n>>m>>k)
    {
        if(!n)break;
        memset(pre,-1,sizeof(pre));
        memset(mmap,0,sizeof(mmap));
        for(i=0;i<k;i++)
        {
            cin>>a>>x>>y;
            if(x*y!=0)
            mmap[x][y+n]=1;
        }
        int ans=0;
        for(i=0;i<n;i++)
        {
            memset(vis,0,sizeof(vis));
            ans+=dfs(i);
        }
        cout<<ans<<endl;
    }
}

Machine Schedule
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 11631   Accepted: 4952

Description

As we all know, machine scheduling is a very classical problem in computer science and has been studied for a very long history. Scheduling problems differ widely in the nature of the constraints that must be satisfied and the type of schedule desired. Here we consider a 2-machine scheduling problem. 

There are two machines A and B. Machine A has n kinds of working modes, which is called mode_0, mode_1, ..., mode_n-1, likewise machine B has m kinds of working modes, mode_0, mode_1, ... , mode_m-1. At the beginning they are both work at mode_0. 

For k jobs given, each of them can be processed in either one of the two machines in particular mode. For example, job 0 can either be processed in machine A at mode_3 or in machine B at mode_4, job 1 can either be processed in machine A at mode_2 or in machine B at mode_4, and so on. Thus, for job i, the constraint can be represent as a triple (i, x, y), which means it can be processed either in machine A at mode_x, or in machine B at mode_y. 

Obviously, to accomplish all the jobs, we need to change the machine‘s working mode from time to time, but unfortunately, the machine‘s working mode can only be changed by restarting it manually. By changing the sequence of the jobs and assigning each job to a suitable machine, please write a program to minimize the times of restarting machines. 

Input

The input file for this program consists of several configurations. The first line of one configuration contains three positive integers: n, m (n, m < 100) and k (k < 1000). The following k lines give the constrains of the k jobs, each line is a triple: i, x, y. 

The input will be terminated by a line containing a single zero. 

Output

The output should be one integer per line, which means the minimal times of restarting machine.

Sample Input

5 5 10
0 1 1
1 1 2
2 1 3
3 1 4
4 2 1
5 2 2
6 2 3
7 2 4
8 3 3
9 4 3
0

Sample Output

3



POJ1325_Machine Schedule(二分图/最小点覆盖=最大匹配),布布扣,bubuko.com

POJ1325_Machine Schedule(二分图/最小点覆盖=最大匹配)

标签:des   style   blog   http   color   os   strong   io   

原文地址:http://blog.csdn.net/juncoder/article/details/38147135

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