由于公司最近的数据库服务器CPU非常不稳定。
于是乎下手查找问题的来源。想了下,只能从存储过程的执行状态中下手。
查了下资料,发现MSSQL中的系统表sys.dm_exec_procedure_stats会记录存储过程的执行状态数据。字段含义就不累述了。开始干活:
1、将数据插入一张新表记录
select convert(nvarchar(10),getdate(),121) as countdate,d.* into procedure_stats_daily from SYS.procedures S JOIN sys.dm_exec_procedure_stats D ON S.object_id=D.object_id
2、每天作业执行,将数据插入记录表
insert into procedure_stats_daily select convert(nvarchar(10),getdate(),121),d.* from SYS.procedures S JOIN SYS.dm_exec_procedure_stats D ON S.object_id=D.object_id
3、查看时间@Date的执行情况
DECLARE @Date datetime,@Date1 datetime SET @Date=‘2016-03-17‘ SET @Date1=@Date+1 SELECT a.object_id,c.name as ‘存储过程名称‘, CASE WHEN a.cached_time>=@Date THEN ISNULL(a.execution_count,0) ELSE ISNULL(a.execution_count-b.execution_count,0)END as ‘执行次数‘, CASE WHEN a.cached_time>=@Date THEN ISNULL(a.total_worker_time/1000000,0)ELSE ISNULL((a.total_worker_time-b.total_worker_time)/1000000,0)END as ‘执行时间/秒‘, case when ISNULL(a.execution_count-b.execution_count,0)=0 then 0.00 else convert(numeric(18,4),(a.total_worker_time-b.total_worker_time))/(a.execution_count-b.execution_count)/1000000 end as ‘平均执行时间/秒‘ FROM ( select object_id,cached_time,plan_handle,isnull(execution_count,0) as execution_count,isnull(total_worker_time,0)as total_worker_time from procedure_stats_daily where countdate=@Date1 )a FULL JOIN ( select object_id,cached_time,plan_handle,isnull(execution_count,0) as execution_count,isnull(total_worker_time,0)as total_worker_time from procedure_stats_daily where countdate=@Date )b on a.plan_handle=b.plan_handle left join sys.objects c on a.object_id=c.object_id order by CASE WHEN a.cached_time>=@Date THEN ISNULL(a.execution_count,0) ELSE ISNULL(a.execution_count-b.execution_count,0)END desc
根据以上的数据,我们可以查出最频繁的存储过程和效率最低的存储过程,进而给我们的优化工作提供了方向。
本文出自 “sukun” 博客,请务必保留此出处http://sukunwu.blog.51cto.com/10453116/1752607
原文地址:http://sukunwu.blog.51cto.com/10453116/1752607