编写函数:
unsigned int reverse_bit(unsigned int value);
这个函数的返回 值value的二进制位模式从左到右翻转后的值。
如:
在32位机器上25这个值包含下列各位:
00000000000000000000000000011001
翻转后:(2550136832)
10011000000000000000000000000000
程序结果返回:
2550136832
unsigned int reverse_bit1(unsigned int value) { int i = 0; unsigned int ret = 0; for (i = 0; i < 32; i++) { ret += (((value >> i) & 1)<<(31-i)); } return ret; } unsigned int reverse_bit2(unsigned int value) { unsigned int ret = 0; int i = 0; for (i = 0; i < 32; i++) { ret <<= 1; ret |= ((value >> i) & 1); } return ret; } int main() { unsigned int num = 0; scanf("%u", &num); printf("%u", reverse_bit1(num)); //printf("%u", reverse_bit2(num)); system("pause"); return 0; }
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原文地址:http://10707460.blog.51cto.com/10697460/1753165