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题意:
带权联通块,添边与查询联通块中第k大.
SOL:
splay合并+并查集.
我以为splay可以用奇技淫巧来简单合并...调了一下午终于幡然醒悟...于是就只好一个一个慢慢插...什么启发式合并...说的那么高级其实那么丝帛.
实现得非常渣...中序遍历3060ms,换成队列并没有快起来...难道是我的splay本身就不对?...
%%%hzw的线段树...发现其实线段树合并更简单更快...被splay蒙蔽了眼睛...思路不够开阔...唉...
Code:
/*========================================================================== # Last modified: 2016-03-20 10:23 # Filename: 2733.cpp # Description: ==========================================================================*/ #define me AcrossTheSky #include <cstdio> #include <cmath> #include <ctime> #include <string> #include <cstring> #include <cstdlib> #include <iostream> #include <algorithm> #include <set> #include <map> #include <stack> #include <queue> #include <vector> #define lowbit(x) (x)&(-x) #define FOR(i,a,b) for((i)=(a);(i)<=(b);(i)++) #define FORP(i,a,b) for(int i=(a);i<=(b);i++) #define FORM(i,a,b) for(int i=(a);i>=(b);i--) #define ls(a,b) (((a)+(b)) << 1) #define rs(a,b) (((a)+(b)) >> 1) #define getlc(a) ch[(a)][0] #define getrc(a) ch[(a)][1] #define maxn 400000 #define maxm 100000 #define pi 3.1415926535898 #define _e 2.718281828459 #define INF 1070000000 using namespace std; typedef long long ll; typedef unsigned long long ull; template<class T> inline void read(T& num) { bool start=false,neg=false; char c; num=0; while((c=getchar())!=EOF) { if(c==‘-‘) start=neg=true; else if(c>=‘0‘ && c<=‘9‘) { start=true; num=num*10+c-‘0‘; } else if(start) break; } if(neg) num=-num; } /*==================split line==================*/ int ch[maxn][2],fa[maxn],father[maxn],sz[maxn],key[maxn]; void pushup(int x){ sz[x]=sz[ch[x][0]]+sz[ch[x][1]]+1; } int kth(int x,int k){ while (x){ if (k==sz[ch[x][0]]+1) return x; if (k>sz[ch[x][0]]+1) k-=sz[ch[x][0]],k--,x=ch[x][1]; else x=ch[x][0]; } } int find(int x){ return father[x]==x?x:find(father[x]); } void rotate(int x){ int p=fa[x],q=fa[p],d=ch[p][1]==x; fa[ch[p][d]=ch[x][d^1]]=p; pushup(p); fa[ch[x][d^1]=p]=x;pushup(x); fa[x]=q; if (q){ if (ch[q][1]==p) ch[q][1]=x; else ch[q][0]=x; } } void splay(int x,int aim){ for (int y;(y=fa[x])!=aim;rotate(x)) if (fa[y]!=aim) rotate((getlc(y)==x)==(getlc(fa[y])==y)?y:x); } void insert(int x,int root){ int node=root; while (node){ sz[node]++; int &d=ch[node][key[node]<key[x]]; if (d==0) { d=x; fa[x]=node; ch[x][0]=ch[x][1]=0; sz[x]=1; node=x; break; } node=d; } //splay(node,0); } int q[maxn]; void join(int x,int root){ /*int lc=ch[x][0],rc=ch[x][1]; ch[x][0]=ch[x][1]=0; if (lc) { join(lc,root); } //ch[x][1]=0; fa[rc]=0; insert(x,root); if (rc) join(rc,root);*/ int head=1,tail=1; q[head]=x; while (head<=tail){ x=q[head]; head++; int lc=ch[x][0],rc=ch[x][1]; ch[x][0]=ch[x][1]=0; insert(x,root); if (lc) q[++tail]=lc; if (rc) q[++tail]=rc; } } void Union(int x,int y){ int u=find(x),v=find(y); if (u==v) return; else { father[u]=v; splay(u,0); splay(v,0); if (sz[u]<sz[v]) join(u,v); else join(v,u);/*father[u]=v; int a=kth(u,1),b=kth(v,sz[v]); splay(a,0); splay(b,0); if (key[a]<key[b]) {ch[a][1]=b; fa[b]=a; pushup(a);} else {ch[b][1]=a; fa[a]=b; pushup(b);} */ } } void query(int x,int k){ splay(x,0); if (k>sz[x]) printf("-1\n"); else printf("%d\n",kth(x,k)); } int main(){ int n,m; read(n); read(m); memset(father,0,sizeof(father)); FORP(i,1,n) { read(key[i]); father[i]=i; sz[i]=1;} FORP(i,1,m){ int u,v; read(u); read(v); Union(u,v); } int q; read(q); FORP(i,1,q){ char ch[10]; scanf("%s",ch); if (ch[0]==‘Q‘) { int x,k; read(x); read(k); query(x,k); } else { int u,v; read(u); read(v); Union(u,v);} } }
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原文地址:http://www.cnblogs.com/YCuangWhen/p/5300523.html