标签：
我复审的是胡新宇的代码，我参考了教材的内容，根据教材一步一步地进行了复审，我首先通过VS2015进行了运行，程序可以运行出来，通过测试四则运算程序也没有发生乱码或者闪退等bug。然后我又一步一步地分析他每一行代码的内容和含义，可以很清楚明白的看出他的思想还有要完成的内容。通过对他的代码复审发现其中有很多值得我学习的地方，就如同作业第一道题是一样的，他有着非常严格的代码规范，每一行都可以清楚的看出他思想，而 且代码也没有出现繁复。以后要向他学习。
附其部分代码以便日后学习参考：
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<math.h>
void Shengcheng();
void Simple();
void real();
void result();
int MaxGYS(int a, int b);
int system(const char *string);
int main(void)
{
int n;
Loop1: printf("\n\n\n\n\t\t\t耿丹13计科-1胡新宇\n\n\t\t\t[1] 小学数学无分数十道四则运算练习题\n\n\t\t\t[2]小学数学分数四则运算练习题\n\n\t\t\t[3] 退出程序\n\n\t\t\t请输入相应的选项,按回车键确定:");
scanf_s("%d", &n);
system("cls");
if (n == 1)
Shengcheng();//到整数十道题界面
else
if (n == 2)
result();//分数界面
else
if (n == 3)
{
printf("\n\n\n\n\n\n\t\t再见\n\n\t\t");//退出界面
return 0;
}
else
printf("输入错误请重新输入");//错误提示
goto Loop1;//回到主界面
return 0;
}
void Shengcheng()//整数十道运算随机题
{
int i, a, b, p, q, r, c, sum = 0, d = 0, e = 0;
srand((unsigned)time(NULL));
printf("请做下面十道四则运算题，加油哦！\n\n");
for (i = 0; i < 10; i++)
{
a = rand() % 50;
b = rand() % 50;
p = rand() % 50;
q = rand() % 50;
r = rand() % 50;
while (r == 0)
{
i--;
}
while (r != 0)
{
printf("请输入你的答案：%d+%d-%d*%d/%d=", a, b, p, q, r);
scanf_s("%d", &c);
printf("\n");
if ((a + b - p*q / r) == c)
{
printf("恭喜你答对了！干的不错！\n\n");
sum = sum + 10;
e = e + 1;
}
else
{
printf("答案错误！请继续努力！\n\n");
d = d + 1;
}
break;//返回
}
continue;
}
printf("你总共答对了%d道题，答错了%d道题。\n\n", e, d);
printf("你的得分为：%d分继续努力哟！\n\n", sum);
return ;
}
void Simple()
{
int m, b, c, d, t;
m = rand() % 3 + 1;
b = rand() % 20 + 1;
c = rand() % 20 + 1;
switch (m)
{
case 1: {
d = b + c;
printf("%d+%d=\t\t\t\t\t\t\t\t\t%d\n", b, c, d);
}break;
case 2: {
if (b>c)
{
t = b;
b = c;
c = t;
}
d = b - c;
printf("%d-%d=\t\t\t\t\t\t\t\t\t%d\n", b, c, d);
}break;
case 3: {
d = b*c;
m = rand() % 2 + 1;
if (m == 1)
printf("%d*%d=\t\t\t\t\t\t\t\t\t%d\n", b, c, d);
else
printf("%d/%d=\t\t\t\t\t\t\t\t\t%d\n", d, b, c);
} break;
}
return;
}
void real()//分子分母
{
int a, b, c, d, e, f, g, h, t;
a = rand() % 4 + 1;
b = rand() % 9 + 1;//第一个数字分子
c = rand() % 9 + 1;//第一个数字分母
d = rand() % 9 + 1;//第二个数字分子
e = rand() % 9 + 1;//第二个数字分母
if (b>c)
{
t = b;
b = c;
c = t;
}
if (d>e)
{
t = d;
d = e;
e = t;
}
switch (a)
{
case 1: {
f = c*e;
g = b*e + d*c;
h = MaxGYS(g, f);
f = f / h;
g = g / h;
printf("(%d/%d)+(%d/%d)=\t\t\t\t\t\t\t\t(%d/%d)\n", b, c, d, e, g, f);
}break;
case 2: {
f = c*e;
g = b*e - d*c;
if (g>0)
{
h = MaxGYS(g, f);
f = f / h;
g = g / h;
printf("(%d/%d)-(%d/%d)=\t\t\t\t\t\t\t\t(%d/%d)\n", b, c, d, e, g, f);
}
else
{
g = abs(g);
h = MaxGYS(g, f);
f = f / h;
g = g / h;
printf("(%d/%d)-(%d/%d)=\t\t\t\t\t\t\t\t(%d/%d)\n", d, e, b, c, g, f);
}
}break;
case 3: {
f = c*e;
g = b*d;
h = MaxGYS(g, f);
f = f / h;
g = g / h;
printf("(%d/%d)*(%d/%d)=\t\t\t\t\t\t\t\t(%d/%d)\n", b, c, d, e, g, f);
}break;
case 4: {
f = b*e;
g = c*d;
h = MaxGYS(g, f);
f = f / h;
g = g / h;
printf("(%d/%d)/(%d/%d)=\t\t\t\t\t\t\t\t(%d/%d)\n", b, c, d, e, g, f);
}
default:break;
}
return;
}
int MaxGYS(int a, int b)//定义a,b中的最大值为整型变量
{
int c, t;
if (a<b)
{
t = a;
a = b;
b = t;
}
while (b != 0)
{
c = a%b;
a = b;
b = c;
}
return a;
}
void result()//分数四则随机题
{
int m, i;
for (i = 0; i<30; i++)
{
m = rand() % 2 + 1;
if (m == 1)
Simple();
else
real();
}
system("pause");
system("cls");
system("pause");
system("cls");
return ;
}
标签：
原文地址：http://www.cnblogs.com/HAOZHE/p/5308336.html
