结对作业4词频统计

// ConsoleApplication2.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"
#include<iostream>
#include<fstream>
#include<cstring>
using namespace std;

struct Num{
    int num = 1;
    char *s = NULL;
};

Num word[99];

int Judge(char danci[])//判断单词
{
    bool j1 = (strlen(danci) >= 4);
    bool j2 = (danci[0] >= ‘a‘ && danci[0] <= ‘z‘);
    if (!(j1&&j2))
        return -1;
    else
    for (int ns = 1; danci[ns] != ‘\0‘;)
    {
        if (!((danci[ns] >= ‘a‘ && danci[ns] <= ‘z‘) || (danci[ns] >= ‘0‘ && danci[ns] <= ‘9‘)))
            return -1;
        else
            ns++;
    }
}
int Sta(char danci[], int nn)   //判断该单词是否出现过
{
    if (nn>0)
    for (int i = 0; i <nn; i++)
    {
        if (!strcmp(danci, word[i].s))  //出现
        {
            word[i].num++;      //+1
            return -1;
        }
    }
}
int main()
{
    char sentence[1000];//字符数组长度要足够大
    ifstream file("d://A_Tale_of_Two_Cities.txt");  
    ofstream outfile("d://Result1.txt");  //读取
    if (!file){
        cout << "Unable to open file";
        exit(1);
    }
    if (!outfile){
        cout << "Unable to open outmyfile";
        exit(1);
    }
    while (!file.eof())
    {
        file.getline(sentence, 1000);
    }
    file.close();
    int num2 = 0;
    while (sentence[num2] != ‘\0‘)//转小写
    {
        if (sentence[num2] >= ‘A‘&&sentence[num2] <= ‘Z‘)
            sentence[num2] = sentence[num2] + 32;
        num2++;
    }
    const char *delim = " ,“”.‘‘‘’!?";  //分隔符
    char *p,
        *pNext = NULL;
    int n = 0,     //计数器 n ,t 初始化
        t = 0;
    p = strtok_s(sentence, delim, &pNext);   //strtovk_s函数根据分隔符分隔字符串
    while (p)
    {
        if (Judge(p) != -1)
        {
            if (Sta(p, n) != -1)
            {
                word[n].s = p;
                n++;
            }
        }
        p = strtok_s(NULL, delim, &pNext);
    }

    while (word[t].s)        //输出统计结果
    {
        cout<< word[t].s << "：" << word[t].num << ‘\n‘;
        outfile<< word[t].s << "：" << word[t].num << ‘\n‘;
        t++;
}
    outfile.close();
    return 0;
}